80p^2-125=0

Solution for 80p^2-125=0 equation:

80p^2-125=0

a = 80; b = 0; c = -125;
Δ = b2-4ac
Δ = 02-4·80·(-125)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*80}=\frac{-200}{160}
=-1+1/4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*80}=\frac{200}{160}
=1+1/4
$